Solve the system:
\begin{equation*}
\begin{aligned}
x + 2y \amp= 4\\
4x - 5y \amp= 5
\end{aligned}
\end{equation*}
Solution.
Geometrically: we’re finding where the line \(x + 2y = 4\) intersects the line \(4x - 5y = 5\text{.}\)
Algebraically: From the first equation, \(x = 4 - 2y\text{.}\) Substituting into the second:
\begin{align*}
4(4-2y) - 5y \amp= 5\\
16 - 8y - 5y \amp= 5\\
-13y \amp= -11\\
y \amp= \frac{11}{13}
\end{align*}
Then \(x = 4 - 2 \cdot \frac{11}{13} = \frac{30}{13}\text{.}\)
Unique solution: \(\left(\frac{30}{13}, \frac{11}{13}\right)\text{.}\) The lines have different slopes, so they must intersect at exactly one point.
